Find the potential difference across the 24,O | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) First,calculate the equivalent resistance $(R_p)$ of the parallel combination of resistors: $48\,\Omega, 48\,\Omega, 24\,\Omega, 6\,\Omega, 4\,\Om

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) First,calculate the equivalent resistance $(R_p)$ of the parallel combination of resistors: $48\,\Omega, 48\,\Omega, 24\,\Omega, 6\,\Omega, 4\,\Omega,$ and $2\,\Omega$.Using the formula $\frac{1}{R_p} = \frac{1}{48} + \frac{1}{48} + \frac{1}{24} + \frac{1}{6} + \frac{1}{4} + \frac{1}{2}$.$\frac{1}{R_p} = \frac{1+1+2+8+12+24}{48} = \frac{48}{48} = 1\,\Omega^{-1}$.Therefore,$R_p = 1\,\Omega$.The total current flowing through the circuit is $I = 2\,A$.The potential difference across the parallel combination (which includes the $24\,\Omega$ resistor) is $V = I 	imes R_p = 2\,A 	imes 1\,\Omega = 2\,V$.

Find the potential difference across the $24\,\Omega$ resistor in the given circuit. (in $,V$)

Similar Questions

In this circuit,when a certain current flows,the heat produced in the $5 \Omega$ resistor is $4.05 \ J$ in a time $t$. The heat produced in the $2 \Omega$ resistor in the same time interval is: (in $J$)

Write the equation for the equivalent resistance of $n$ resistors connected in series and the equation for the equivalent resistance of $n$ resistors connected in parallel.

Resistance $n$,each of $r \ \Omega$,when connected in parallel give an equivalent resistance of $R \ \Omega$. If these resistances were connected in series,the combination would have a resistance in $\Omega$,equal to

The effective resistance of the network between points $A$ and $B$ is

In the given circuit,find the value of $V$. (in $V$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module